Getting The Resultant Vector
![](http://www.1728.com/vector.gif)
In this section, we will add the same vectors mathematically . To do this, we first must resolve each vector into its horizontal and vertical components. We see from the above formulas that:
X = Horizontal Component = Magnitude * Cos ( q )X= 3 * Cos(45°)X= 3 * 0.707106781186547... = 2.12132034355964 Y = Vertical Component = Magnitude * Sin ( q )Y = 3 * 0.707106781186547... = 2.12132034355964
Moving on to the next vector:X = 6 * Cos(90°) = 0Y = 6 * Sin(90°) = 6
And for the final vector:X = 5 * Cos(150°) = 5 * -0.866025403784439 = -4.33012701892219Y = 5 * Sin(150°) = 5 * .5 = 2.5
Now we sum up the horizontal components (the X values):X sum = 2.12132034355964 + 0 -4.33012701892219 = -2.20880667536255
Summing up the vertical components (the Y values):
Y sum = 2.12132034355964 + 6 + 2.5 = 10.62132034355964
We determine the magnitude of the resultant vector by the Pythagorean Theorem:Magnitude 2 = X2 + Y2Magnitude 2 = -2.208806675362552 + 10.621320343559642Magnitude 2 = 4.87882692912616 + 112.812445840514Magnitude 2 = 117.69127276964Magnitude = 10.848560861683
To determine the direction of the resultant vector the formula is:
ArcTangent (Resultant Vector) = (Ysum / Xsum)
ArcTangent (of Resultant Vector) =10.62132034355964-2.20880667536255)
ArcTangent (of Resultant Vector)= -4.8086237976514
Angle = 101.747770718541 Degrees